Question on: WAEC Mathematics - 1990
Two groups of male students cast their vote on a particular proposal. The results are as follows:
| In favor | Against | |
| Group A | 128 | 32 |
| Group B | 96 | 48 |
If a student is chosen at random, what is probability that he is against the proposal?
A
3/19
B
4/19
C
5/19
D
9/19
Ask EduPadi AI for a detailed answer
Correct Option: C
Probability that the student is against the proposal
= \(\frac{32 + 48}{128 + 32 + 96 + 48}\)
= \(\frac{80}{304}\)
= \(\frac{5}{19}\)
Add your answer
Please share this, thanks!
No responses